(2b^2+2b-5)/(b-3)

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Solution for (2b^2+2b-5)/(b-3) equation: 


D( b )

b-3 = 0

b-3 = 0

b-3 = 0

b-3 = 0 // + 3

b = 3

b in (-oo:3) U (3:+oo)

(2*b^2+2*b-5)/(b-3) = 0

2*b^2+2*b-5 = 0

2*b^2+2*b-5 = 0

DELTA = 2^2-(-5*2*4)

DELTA = 44

DELTA > 0

b = (44^(1/2)-2)/(2*2) or b = (-44^(1/2)-2)/(2*2)

b = (2*11^(1/2)-2)/4 or b = (-2*11^(1/2)-2)/4

(b-((-2*11^(1/2)-2)/4))*(b-((2*11^(1/2)-2)/4)) = 0

((b-((-2*11^(1/2)-2)/4))*(b-((2*11^(1/2)-2)/4)))/(b-3) = 0

( b-((-2*11^(1/2)-2)/4) )

b-((-2*11^(1/2)-2)/4) = 0 // + (-2*11^(1/2)-2)/4

b = (-2*11^(1/2)-2)/4

( b-((2*11^(1/2)-2)/4) )

b-((2*11^(1/2)-2)/4) = 0 // + (2*11^(1/2)-2)/4

b = (2*11^(1/2)-2)/4

b in { (-2*11^(1/2)-2)/4, (2*11^(1/2)-2)/4 }

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